WAEC - Further Mathematics (2008 - No. 8)
If \(2\log_{4} 2 = x + 1\), find the value of x.
-2
-1
0
1
Paskaidrojums
\(2\log_{4} 2 = x + 1\)
\(\log_{4} 2^{2} = \log_{4} 4 = 1\)
\(x + 1 = 1 \implies x = 0\)
\(2\log_{4} 2 = x + 1\)
\(\log_{4} 2^{2} = \log_{4} 4 = 1\)
\(x + 1 = 1 \implies x = 0\)