JAMB - Physics (2024 - No. 78)
Calculate the power of an object which moves through a distance of 500cm in 1s on a frictionless surface by a horizontal force of 50N
200W
300W
350W
250W
Paskaidrojums
Power = \(\frac{w}{t}\)
Given: F = 50N, s = 500cm → 5m and t = 1s
W = f x s = 250 x 5 = 250J
Power = \(\frac{250}{1}\) = 250W