JAMB - Physics (1995 - No. 35)
If the maximum voltage across a 100ohms resistor is 20V, then the maximum power it can dissipate is
5.00W
4.00W
2.00W
25W
Paskaidrojums
P = \(\frac{V^2}{R}\)
= \(\frac{20 \times 20}{100}\)
= 4W
= \(\frac{20 \times 20}{100}\)
= 4W