JAMB - Mathematics (1979 - No. 28)
Find the value of log\(_{10}\)\(\frac{1}{40}\), given that log10\(_4\) = 0.6021
1.3979
2.3979
-1.6021
2.6021
Paskaidrojums
log\(_{10}\)\(\frac{1}{40}\) = log\(_{10}\)1 - (log\(_{10}\)4 + log\(_{10}\)10)
= 0 - 1.6021
= -1.6021
= 0 - 1.6021
= -1.6021