ExamPlay Light Logo
Prisijunkite

WAEC - Physics (2017 - No. 37)

A circuit is set up as shown in the diagram above. When the key is closed, the ammeter reading will be

6A
4A
2A
1A

Paaiškinimas

The resistors are connected both in parallel and series. To calculate the total resistance, we have:

For the parallel connection: \(\frac{1}{R} = \frac{1}{1} + \frac{1}{1}\)

\(\frac{1}{R} = 2 \implies R = 0.5\Omega\)

For the series connection: \(R_{total} = (1 + 0.5)\Omega = 1.5\Omega\)

Recall, \(V=IR\)

\(3 = 1.5I  \implies I = \frac{3}{1.5} =2A\)

Komentarai (0)

Prisijungti Norėdami komentuoti
Skelbimas
BrainBehindX Inc Logo
©2026; Maitinamas BrainBehindX Inc