WAEC - Physics (2015 - No. 36)
An electric generator rated 12 kW, 2 kV distribute power through a cable of resistance 20\(\Omega\). Calculate the power loss in the cable.
120 w
360 w
720 w
2400 w
Paaiškinimas
Power - IV
I = \(\frac{P}{V}\)
= \(\frac{12000}{2000}\)
I = 6A
Power loss = I\(^2\)R = 6\(^2\) x 20
= 720 W
I = \(\frac{P}{V}\)
= \(\frac{12000}{2000}\)
I = 6A
Power loss = I\(^2\)R = 6\(^2\) x 20
= 720 W