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WAEC - Mathematics (2001 - No. 38)

In the diagram, PQ is a diameter of the circle and ∠PRS = 58°. Find ∠STQ.

29o
32o
42o
53o

Paaiškinimas

In \(\Delta\) PRQ, < SRQ = 90° - 58°

< SRQ = < QTS = x (angles in the segment)

\(\therefore\) x = 32°

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