WAEC - Mathematics (1992 - No. 20)
In the diagram above, O is the center of the circle and ∠POR = 126°. Find ∠PQR
234o
117o
72o
63o
54o
Paaiškinimas
Reflex < POR = 360° - 126° = 234°
\(\therefore\) < PQR = \(\frac{1}{2} \times 234°\)
= 117°
In the diagram above, O is the center of the circle and ∠POR = 126°. Find ∠PQR
Reflex < POR = 360° - 126° = 234°
\(\therefore\) < PQR = \(\frac{1}{2} \times 234°\)
= 117°