WAEC - Mathematics (1988 - No. 35)
In the diagram above, PR is perpendicular from P to QS, PQ = 2cm, QR = 1cm and PR = RS. what is the size of the angle QPS?
135o
105o
90o
75o
60o
Paaiškinimas
\(\Delta RPS\) = Isosceles triangle
\(\therefore < RPS = \frac{180° - 90°}{2}\)
= 45°
In \(\Delta QPR\),\(\sin < QPR = \frac{1}{2}\)
= 30°
\(\therefore < QPS = 30° + 45° = 75°\)