WAEC - Mathematics (1988 - No. 26)
In the diagram above, O is the center of the circle, BOC is a diameter and angle ADC is 37o
What is ACB?
147o
127o
65o
53o
37o
Paaiškinimas
From the figure \(< ABC = < ADC = 37°\) (angles on the same segment)
\(< BCA = 90°\) (angle in semi-circle)
\(\therefore\) In \(\Delta ABC\), \(< ACB = 180° - (37° + 90°)\)
= 53°