ExamPlay Light Logo
Prisijunkite

WAEC - Further Mathematics (2010 - No. 8)

If (x - 3) is a factor of \(2x^{2} - 2x + p\), find the value of constant p.
-12
-6
3
6

Paaiškinimas

Using remainder theorem, since x - 3 is a factor, then 

given \(2x^{2} - 2x + p\), f(3) = 0

\(2(3^{2}) - 2(3) + p = 0 \implies 18 - 6 = -p\)

\(p = -12\)

Komentarai (0)

Prisijungti Norėdami komentuoti
Skelbimas
BrainBehindX Inc Logo
©2026; Maitinamas BrainBehindX Inc