ExamPlay Light Logo
Prisijunkite

JEE Advance - Mathematics (1998 - No. 39)

If $$f\left( x \right) = {{{x^2} - 1} \over {{x^2} + 1}},$$ for every real number $$x$$, then the minimum value of $$f$$
does not exist because $$f$$ is unbounded
is not attained even though $$f$$ is bounded
is equal to 1
is equal to -1

Komentarai (0)

Prisijungti Norėdami komentuoti
Skelbimas
BrainBehindX Inc Logo
©2026; Maitinamas BrainBehindX Inc