JEE MAIN - Chemistry (2006 - No. 46)
According to Bohr's theory, the angular momentum of an electron in 5th orbit is
10 $$h/\pi$$
2.5 $$h/\pi$$
25 $$h/\pi$$
1.0 $$h/\pi$$
Paaiškinimas
Formula of angular momentum of an electron,
mvr = $${{nh} \over {2\pi }}$$
here n = 5
$$\therefore$$ mvr = $${{5h} \over {2\pi }}$$ = 2.5$${{h} \over {\pi }}$$
mvr = $${{nh} \over {2\pi }}$$
here n = 5
$$\therefore$$ mvr = $${{5h} \over {2\pi }}$$ = 2.5$${{h} \over {\pi }}$$