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JAMB - Physics (1995 - No. 9)
The energy contained in a wire when it extended by 0.02m by a force 500 N is
5J
10J
10
3
J
10
4
Paaiškinimas
Energy = \(\frac{1}{2}\)Fe
= \(\frac{1}{2}\) x 500 x 0.02
E = 5J
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