JAMB - Physics (1991 - No. 26)
Which of the following correctly, describes the image of an object, 4cm from a diverging lens of focal length 12cm?
The image is virtual, 3cm in front of the lens
The image is real, 6cm behind the lens
The image is virtual, 6cm in front of the lens
The image is real, 3cm in front the lens
Paaiškinimas
F = \(\frac{uv}{u + v}\)
F = -ve
-12 = \(\frac{4 \times v}{4 + v}\)
v = -3cm
F = -ve
-12 = \(\frac{4 \times v}{4 + v}\)
v = -3cm