JAMB - Physics (1989 - No. 7)
A piece of wood of mass 40g and uniform cross-sectional area of 2cm2 floats upright in water. The length of the wood immersed is
30cm
40cm
20cm
2cm
Paaiškinimas
Mw displaced = 40g
density = \(\frac{mass}{\text{area x height}}\)
I = \(\frac{40}{2\times h}\)
h = 20cm
density = \(\frac{mass}{\text{area x height}}\)
I = \(\frac{40}{2\times h}\)
h = 20cm