JAMB - Mathematics (2010 - No. 5)
Factorize completely \(\frac{x^{3} + 3x^{2} - 10x}{2x^{2} - 8}\)
| x(x-5) |
| 2(x+2) |
| x(x-5) |
| 2(x-2) |
| x(x+5) |
| 2(x+2) |
| x2+5 |
| 2x+4 |
Paaiškinimas
\(\frac{x^{3} + 3x^{2} - 10x}{2x^{2} - 8} = \frac{x(x^{2} + 3x - 10)}{2(x^{2} - 4)}\)
= \(\frac{x(x^{2} - 2x + 5x - 10)}{2(x - 2)(x + 2)}\)
= \(\frac{x(x - 2)(x + 5)}{2(x - 2)(x + 2)}\)
= \(\frac{x(x + 5)}{2(x + 2)}\)