JAMB - Mathematics (2004 - No. 3)
The sum of the interior angles of a pentagon is 6x + 6y. Find y in the terms of x
y = 90 - x
y = 150 - x
y = 60 - x
y = 120 -x
Paaiškinimas
6x + 6y = (n - 2) 180
6x + 6y= (5 - 2) 180
6(x + y) = 3 * 180
x + y = (3 * 180)/6
x + y = 90o
y = 90 - x
6x + 6y= (5 - 2) 180
6(x + y) = 3 * 180
x + y = (3 * 180)/6
x + y = 90o
y = 90 - x