JAMB - Mathematics (1987 - No. 26)
Find the eleventh term of the progression 4, 8, 16.....
213
212
211
210
Paaiškinimas
a = 4, r = \(\frac{4}{2}\)
\(\frac{8}{4}\) = 2
n = 11
Tn = arn - 1
T11 = 4(2)11 - 1
4(2)10 = 212
since 4 = 22
= 212
\(\frac{8}{4}\) = 2
n = 11
Tn = arn - 1
T11 = 4(2)11 - 1
4(2)10 = 212
since 4 = 22
= 212