WAEC - Physics (1991 - No. 13)
A water fall is 420m high. Calculate the difference in temperature of the water between the top and bottom of the water fall. Neglect heat loses(g = 10.0m-2 specific heat capacity of water = 4.20 x 10\(^3\) JKg-1 K-1)
0.1oC
1.0oC
42oC
100oC
4.20oC
설명
Potential Energy = Heat Energy
mgh = Mc\(\Delta \theta = \frac{gh}{c} = \frac{10 \times 240}{4.20 \times 10^3}\)
= 1.0oC
mgh = Mc\(\Delta \theta = \frac{gh}{c} = \frac{10 \times 240}{4.20 \times 10^3}\)
= 1.0oC