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WAEC - Mathematics (2006 - No. 37)

In the diagram, PR is a diameter of the circle centre O. RS is a tangent at R and QPR = 58o. Find < QRS
112o
116o
122o
148o

설명

PRQ = 90 - 58 = 32o(angle in a semi-circle)

Since PRS = 90o(radius angular to tangent)

QRS = 90 + 32

= 122o

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