WAEC - Mathematics (1998 - No. 22)
Given that \(\frac{6x-y}{x+2y}=2\), find the value of \(\frac{x}{y}\)
\(\frac{3}{8}\)
\(\frac{5}{8}\)
\(\frac{4}{5}\)
\(\frac{5}{4}\)
\(\frac{8}{5}\)
설명
\(\frac{6x-y}{x+2y}=2\)
→ \((6x-y) = (x+2y)2\)
= 6x - y = 2x + 4y
Collect like terms: 6x - 2x = 4y + y
→ 4x = 5y
\(\frac{x}{y} = \frac{5}{4}\)