WAEC - Further Mathematics (2021 - No. 17)
If 2y\(^2\) + 7 = 3y - xy, find \(\frac{dy}{dx}\)
\(\frac{-y}{4x+y-3}\)
\(\frac{y}{4x+y-3}\)
\(\frac{y}{4x+x-3}\)
\(\frac{ -y}{4y+ x -3}\)
설명
2y\(^2\) + 7 = 3y - xy, find \(\frac{dy}{dx}\)
4y\(\frac{dy}{dx}\) + 0 = 3 \(\frac{dy}{dx}\) - (x\(\frac{dy}{dx}\) + y)
{4y+ x - 3}\(\frac{dy}{dx}\) = - y
= \(\frac{-y}{4y + x - 3}\)