WAEC - Further Mathematics (2019 - No. 1)
Solve: 8\(^{x - 2}\) = 4\(^{3x}\)
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-1
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설명
8\(^{x - 2}\) = 4\(^{3x}\)
2\(^{3(x - 2)}\) = 2\(^{2(3x)}\)
2 \(^{3x - 4}\) = 2\(^{6x}\)
2 \(^{x - 4}\) = 6\(^x\)
\(\frac{-4x}{-4}\) = \(\frac{4}{-4}\)
x = -1
Solve: 8\(^{x - 2}\) = 4\(^{3x}\)
8\(^{x - 2}\) = 4\(^{3x}\)
2\(^{3(x - 2)}\) = 2\(^{2(3x)}\)
2 \(^{3x - 4}\) = 2\(^{6x}\)
2 \(^{x - 4}\) = 6\(^x\)
\(\frac{-4x}{-4}\) = \(\frac{4}{-4}\)
x = -1