ExamPlay Dark Logo
로그인

JEE Advance - Mathematics (1983 - No. 28)

If $${\left( {1 + ax} \right)^n} = 1 + 8x + 24{x^2} + .....$$ then $$a=..........$$ and $$n =............$$
a = 1, n = 8
a = 8, n = 1
a = 4, n = 2
a = 2, n = 4
a = 3, n = 6

댓글 (0)

광고