JEE Advance - Chemistry (2000 - No. 5)
Write down the M.O. electron distribution of O2. Specify its bond order and magnetic property.
σ2s2σ2s*2σ2p2π2p4π2p*2, Bond order=2, Paramagnetic
σ2s2σ2s*2σ2p2π2p4π2p*1, Bond order=2.5, Diamagnetic
σ2s2σ2s*2σ2p2π2p4π2p*3, Bond order=1.5, Paramagnetic
σ2s2σ2s*2σ2p2π2p3π2p*3, Bond order=1, Diamagnetic
σ2s2σ2s*2σ2p1π2p4π2p*3, Bond order=0, Paramagnetic