JEE MAIN - Mathematics Hindi (2002 - No. 14)

यदि $$y = {\left( {x + \sqrt {1 + {x^2}} } \right)^n},$$ तो $$\left( {1 + {x^2}} \right){{{d^2}y} \over {d{x^2}}} + x{{dy} \over {dx}}$$ है