density of methanol =  800kgm\(^{-3}\) → 0.8gcm\(^{-3}\) 

At equilibrium, the density of methanol = the density of liquid x

\(\rho\) x h x g = \(\rho\)\(_x\) x h\(_x\) x g

0.8 x 7.1 = \(\rho\)\(_x\) x 14.2

 \(\rho\)\(_x\) = \(\frac{0.8\times7.1}{14.2}\) = 0.4gcm\(^{-3}\) 

\(\therefore\), the relative density of liquid x = 0.4

Relative density of X = \(\frac{\text{density of liquid x}}{\text{density of methanol}}\) = \(\frac{0.4}{0.8}\) = 0.5