JAMB - Physics (2024 - No. 107)
Calculate the value of electric field intensity due to a charge of 4μC if the force due to the charge is 8N
2.0 x 10\(^6\)NC\(^{-1}\)
3.0 x 10\(^6\)NC\(^{-1}\)
4.0 x 10\(^6\)NC\(^{-1}\)
8.0 x 10\(^6\)NC\(^{-1}\)
설명
Electric field intensity(E) = \(\frac{\text{Force}}{\text{charge}}\) = \(\frac{F}{q}\)
q = 4μC = 4.0 x 10\(^{-6}\)C
F = 8N
E = \(\frac{8}{4.0 \times 10^{-6}}\) = 2.0 x 10\(^6\)NC\(^{-1}\)