JAMB - Physics (2018 - No. 1)
A man walks 1km due east and then 1 km due north His displacement?
√2km N 45°E
1km N 30°E
1km N 15°E
√2km N 60°E
설명
His movements 1km due east and then 1 km due north make a Right-Angled Triangle.
Using Pythagoras' theorem;
The Resultant becomes the Hypotenuse [h]
Hyp\(^2\) = Adj\(^2\) + \Opp(^2\)
Hyp\(^2\) = 1\(^2\) + 1\(^2\)
Hyp\(^2\) = 2 → Hyp = √2
: Resultant = √2
DIRECTION TAN Ø = \(\frac{OPP}{ADJ}\)
TAN Ø = \(\frac{1}{1}\)
Ø = TAN\(^{-1}\) [1]
Ø= 45°
Displacement is √2km N 45°E