JAMB - Physics (2012 - No. 34)
A particle carrying a charge of 1. 0 x 10-8C enters a magnetic field at 3.0x 10-2 ms -1 at right angles to the field. If the force on this particle is 1.8 x 10-8N, what is the magnitude of the field?
6.0x10-1T
6.0x10T
6.0x10-3T
6.0x10-4T
설명
F = BQV
B = \(\frac{F}{QV}\)
B = \(\frac{1.8 \times 10^{-8}}{1.0 \times 10^{-8} \times 3.0 \times 10^{-2}}\)
B = \(\frac{F}{QV}\)
B = \(\frac{1.8 \times 10^{-8}}{1.0 \times 10^{-8} \times 3.0 \times 10^{-2}}\)