ExamPlay Light Logo
로그인

JAMB - Physics (2012 - No. 10)

If a load of 1 kg stretches a cord by 1.2cm, what is the force constant of the cord? {g=10ms-2}
866Nm-1
833Nm-1
769Nm-1
667Nm-1

설명

K = \(\frac{F}{e}\)

K = \(\frac{1 \times 10}{\frac{0.2}{100}}\)

K = \(\frac{10}{12} \times \frac{1000}{1}\)

댓글 (0)

댓글을 달려면 로그인하세요
광고
BrainBehindX Inc Logo
©2026; 에 의해 구동 BrainBehindX Inc