JAMB - Physics (1993 - No. 2)
The external and internal diameter of a tube are measured as (32 ± 2)mm and (21 ± 1)mm respectively. Determine the percentage error in the thickness of the tube.
27%
14%
9%
3%
설명
Actual thickness = 34 - 22 = 12
error thickness = 30 - 20 = 10
error = 12 - 10 = 2mm that is, (11 ± 1)mm
%error = \(\frac{1}{11}\) x \(\frac{100}{1}\)
= 9%
error thickness = 30 - 20 = 10
error = 12 - 10 = 2mm that is, (11 ± 1)mm
%error = \(\frac{1}{11}\) x \(\frac{100}{1}\)
= 9%