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JAMB - Physics (1988 - No. 22)

Two strings of the same length and under the same tension gives notes of frequencies in the ratio 4 : 1. The masses of the strings are in the corresponding ratio of
2 : 1
1 : 2
1 : 4
1 : 16

설명

F = \(\frac{1}{2L}\)\(\sqrt\frac{T}{m}\)

\(\frac{F_1}{F_2}\) = \(\sqrt\frac{m_2}{m_1}\)

\(\frac{1}{4}\) = \(\sqrt\frac{m_2}{m_1}\)

\(\frac{m_2}{m_1}\) = \(\frac{1}{16}\)

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