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JAMB - Mathematics (1988 - No. 33)

The solution of the quadratic equation px2 + qx + b = 0 is
\(\sqrt{\frac{-b \pm b^2 - 4ac}{2a}}\)
\(\frac{-b \pm \sqrt{ p^2 - 4pb}}{2a}\)
\(\frac{-q \pm \sqrt{ q^2 - 4bp}}{2p}\)
\(\frac{-q \pm \sqrt{ p^2 - 4bp}}{2p}\)

설명

px2 + qx + b = 0

Using almighty formula

\(\frac{-b \pm \sqrt{ b^2 - 4ac}}{2a}\).........(i)

Where a = p, b = q and c = b

substitute for this value in equation (i)

= \(\frac{-q \pm \sqrt{ q^2 - 4bp}}{2p}\)

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