JAMB - Chemistry (1980 - No. 6)
On heating, under suitable conditions, 1 litres of monoatomic gas,X, combines with 1½ litres of an oxide, What is the formula of the oxide?
XO3
X2O3
X3O2
XO2
None of the above
설명
To determine the formula of the oxide, let's analyze the given information:
Stoichiometrically, 2 X + 3/2 O\(_2\) → Oxide
Given :
1. 1 litre of monoatomic gas X combines with 1.5 litres of an oxide.
2. The reaction is a combination reaction, where X reacts with oxygen to form an oxide.
If the atom of the elements are X and O\(_2\)
Reacted volumes were given as 1dm\(^3\) 1.5dm\(^3\)
Stoichiometrically, moles of molecules 2 moles 3 moles
X(monoatomic) and oxygen(diatomic) 2 x 1 3 x 2 = 6 (3 moles of O\(_2\) = 6 oxygen atoms)
Divide ratios by 2 \(\frac{2}{2}\) \(\frac{6}{2}\)
The formula ratio : 1 : 3
Therefore, the formula of the oxide is XO\(_3\)