WAEC - Physics (2012 - No. 4)
A block of wood of density 0.6 gcm\(^{-3}\), weighing 3.06N in air, floats freely in a liquid of density 0.9 gcm\(^{-3}\). Calculate volume of the portion immersed (g = 10ms\(^{-2}\))
510cm3
340cm3
254cm3
170cm3
ახსნა
V = \(\frac{M}{D}\)
= \(\frac{3.06}{10} \times \frac{1000}{0.9} = 340\)
= \(\frac{3.06}{10} \times \frac{1000}{0.9} = 340\)