JAMB - Physics (1997 - No. 5)
Two bodies X and Y are projected on the same horizontal plane, with the same initial speed but at angles 30 and 60 respectively to the horizontal. Neglecting air resistance, the ratio of the range of X to that of Y is
1:1
1:2
√3:1
√3
ახსნა
Range = \(\frac{U^2sin2{\theta}}{g}\)
\(\frac{R_x}{R_y}\) = \(\frac{U^2_xsin60}{U^2_ysin120}\)
sin60o = sin120o
\(\frac{R_x}{R_y}\) = \(\frac{1}{1}\)
hence, = 1:1
\(\frac{R_x}{R_y}\) = \(\frac{U^2_xsin60}{U^2_ysin120}\)
sin60o = sin120o
\(\frac{R_x}{R_y}\) = \(\frac{1}{1}\)
hence, = 1:1