WAEC - Physics (2008 - No. 41)
A direct current of 5A flow through a 0.2H inductor. Calculate the energy stored in the inductor
0.5J
1.0J
2.5J
5.0J
説明
P = \(\frac{1}{2} I^2 L\)
= 5\(^2 \times\) 0.2 \(\times\) \(\frac{1}{2}\)
= 2.5J
P = \(\frac{1}{2} I^2 L\)
= 5\(^2 \times\) 0.2 \(\times\) \(\frac{1}{2}\)
= 2.5J