WAEC - Mathematics (1995 - No. 4)
Given that log2a = log84, find a
21/3
42/3
42/3
22/3
23
説明
Log2a = Log84
Log2a = Log882/3 → 2/3Log88 → 2/3 x 1
Log2a = 2/3
Recall; If Logax = y ∴ ay = x
Log2a = 2/3
22/3 = a
Log2a = Log882/3 → 2/3Log88 → 2/3 x 1
Log2a = 2/3
Recall; If Logax = y ∴ ay = x
Log2a = 2/3
22/3 = a