WAEC - Further Mathematics (2021 - No. 2)
For what range of values of x is x\(^2\) - 2x - 3 ≤ 0
{x: -1 ≤ x ≤ 3}
{ x: -3 ≤ x ≤ 1}
{ x: -3 ≤ x ≤ -1}
{ x: 1 ≤ x ≤ 3}
説明
Let x\(^2\) - 2x - 3 = 0;
(x+1)(x-3) = 0
The zeros of the function are x = -1 and 3
The solution set is { x: -1 ≤ x ≤ 3}