ExamPlay Light Logo
サインイン

JEE Advance - Mathematics (1979 - No. 5)

If $$\alpha + \beta + \gamma = 2\pi ,$$ then
$$tan{\alpha \over 2} + \tan {\beta \over 2} + \tan {\gamma \over 2} = \tan {\alpha \over 2}\tan {\beta \over 2}\tan {\gamma \over 2}$$
$$\tan {\alpha \over 2}\tan {\beta \over 2} + \tan {\beta \over 2}\tan {\gamma \over 2} + \tan {\gamma \over 2}\tan {\alpha \over 2} = 1$$
$$tan{\alpha \over 2} + \tan {\beta \over 2} + \tan {\gamma \over 2} = - \tan {\alpha \over 2}\tan {\beta \over 2}\tan {\gamma \over 2}$$
None of these.

コメント (0)

コメントするにはログインしてください
広告
BrainBehindX Inc Logo
©2026; 搭載 BrainBehindX Inc