JEE Advance - Mathematics (1979 - No. 11)
deduce the condition that the equations have a common root.
q(r - p)^2 - r(r - p)(s - q) + (s - q)^2; (q - s)^2 = (r - p)(ps - qr)
q(r - p)^2 - p(r - p)(s - q) + (s - q)^2; (q - s)^2 = (r - p)(ps - qr)
q(r + p)^2 - p(r - p)(s - q) + (s - q)^2; (q - s)^2 = (r - p)(ps - qr)
q(r - p)^2 - p(r - p)(s - q) - (s - q)^2; (q - s)^2 = (r - p)(ps - qr)
q(r - p)^2 - p(r - p)(s - q) + (s - q)^2; (q + s)^2 = (r - p)(ps - qr)