JAMB - Physics (2006 - No. 12)
An electric heater with a p.d of 240 V connected across its terminals has a total resistance of 960Ω. find the power rating of the heater.
0.25 W
4.00 W
38.40W
60.00W
説明
Electrical power = IV or I2R or (V)/R
With V = 240v, R = 960Ω
Power (V2)/R = (240 X 240)/960
=60Watts
With V = 240v, R = 960Ω
Power (V2)/R = (240 X 240)/960
=60Watts