JAMB - Mathematics (2012 - No. 29)
If y = x2 - \(\frac{1}{x}\), find \(\frac{\delta y}{\delta x}\)
2x - \(\frac{1}{x^2}\)
2x + x2
2x - x2
2x + \(\frac{1}{x^2}\)
説明
y = x2 - \(\frac{1}{x}\)
y = x2 - x-1
\(\frac{\delta y}{\delta x}\) = 2x + x-2
\(\frac{\delta y}{\delta x}\) = 2x + \(\frac{1}{x^2}\)
y = x2 - x-1
\(\frac{\delta y}{\delta x}\) = 2x + x-2
\(\frac{\delta y}{\delta x}\) = 2x + \(\frac{1}{x^2}\)