JAMB - Mathematics (1979 - No. 21)
PQRS is a cyclic quadrilateral with PQ as diameter of the circle. If < PQS = 15o find < QRS
75o
37\(\frac{1}{2}\)o
127\(\frac{1}{2}\)o
105o
説明
PSO = 90o(angle in a semicircle)
SPO = 180o - (90o + 15o) = 75o
< QRS = 108o - 75o
= 105o(opposite angles in cyclic quadrilateral are supplementary)
SPO = 180o - (90o + 15o) = 75o
< QRS = 108o - 75o
= 105o(opposite angles in cyclic quadrilateral are supplementary)