WAEC - Mathematics (2003 - No. 13)

Evaluate \(\frac{log8}{log\left(\frac{1}{4}\right)}\)

-2

\(\frac{-3}{2}\)

\(\frac{1}{2}\)

\(\frac{log8}{log\frac{1}{4}}=\frac{log2^3}{log2^{-2}}=\frac{3log2}{-2log2}=-\frac{3}{2}\)