JEE Advance - Mathematics (1989 - No. 21)
The lines 2x - 3y = 5 and 3x - 4y = 7 are diameters of a circle of area 154 sq. units. Then the equation of this circle is
$${x^2} + {y^2} + 2x - 2y = 62$$
$${x^2} + {y^2} + 2x - 2y = 47$$
$${x^2} + {y^2} - 2x + 2y = 47$$
$${x^2} + {y^2} - 2x + 2y = 62$$c