JEE Advance - Mathematics (1983 - No. 46) | ExamPlay

JEE Advance - Mathematics (1983 - No. 46)

Find all the solution of $$4$$ $${\cos ^2}x\sin x - 2{\sin ^2}x = 3\sin x$$

x = nπ

x = nπ + (-1)^n(π/10)

x = nπ + (-1)^n(-3π/10)

x = nπ + π/2

x = 2nπ

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