JAMB - Mathematics (2014 - No. 42)

In the diagram above, \(\alpha\) = 54^o(alternate angles; KL||MN) < KNM = 2\(\alpha\) (LN is bisector of < KNM) = 108^o

35^o + < KMN + 108^o = 180^o(sum of angles of \(\bigtriangleup\))

< KMN + 143^o = 180^o

< KMN = 180^o - 143^o

= 37^o